Apache XML-RPC Exception Handling

What is the easiest way to extract the original exception from an exception returned via Apache's implementation of XML-RPC?

From stackoverflow John the Statistician

• According to the XML-RPC Spec it returns the "fault" in the xml.

  Is this the "Exception" you are referring to or are you refering to a Java Exception generated while making the XML-RPC call?

  Fault example

  HTTP/1.1 200 OK
  Connection: close
  Content-Length: 426
  Content-Type: text/xml
  Date: Fri, 17 Jul 1998 19:55:02 GMT
  Server: UserLand Frontier/5.1.2-WinNT
  
  <?xml version="1.0"?>
  <methodResponse>
    <fault>
      <value>
        <struct>
        <member>
          <name>faultCode</name>
          <value><int>4</int></value>
        </member>
        <member>
          <name>faultString</name>
          <value>
            <string>Too many parameters.</string>
          </value>
        </member>
        </struct>
      </value>
    </fault>
  </methodResponse>
  

  From ScArcher2

• It turns out that getting the cause exception from the Apache exception is the right one.

  } catch (XmlRpcException rpce) {
      Throwable cause = rpce.getCause();
      if(cause != null) {
          if(cause instanceof ExceptionYouCanHandleException) {
              handler(cause);
          }
          else { throw(cause); }
      }
      else { throw(rpce); }
  }
  

  From John the Statistician