I have the following code block in my xslt;
<xsl:when test="StatusData/Status/Temperature > 27">
<td bgcolor="#ffaaaa">
<xsl:value-of select="StatusData/Status/Temperature" />
</td>
</xsl:when>
But as you might guess when the value is 34,5 instead of 34.5 it is recognised as a string which makes integer comparison not possible. I thought replacing , with . would be solution that needs a char replace. My question is how I can do this or It would be great to know more about string operations in XSLT...
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There is a
translate()function in XPath:test="translate(StatusData/Status/Temperature, ",", ".") > 27"Additionally you should make use of the number function, which converts it's argument to a number (or NaN, if that fails):
test="number(translate(StatusData/Status/Temperature, ",", ".")) > 27.0"See the documentation for
translate()and the documentation fornumber()at w3.org. -
Thanx a lot.
it works but with one simple modification:
test="number(translate(StatusData/Status/Temperature, ',', '.')) > 27.0"
by the way it is not about XSLT it is about XPath :) good to learn...
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In XSL 2 you can also use the full-fledged replace() which even supports regex patterns.
erdogany : thats cool thanks..
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